When confronted with an in-flight medical emergency, pilots and crew can consult staff physicians at a global response center located in Arizona. If the global response center is called, there is a 4.8 percent chance that the flight will be diverted for an immediate landing. Suppose the response center is called 8,465 times in a given year.

This question is not complete, the complete question is;

When confronted with an in-flight medical emergency, pilots and crew can consult staff physicians at a global response center located in Arizona. If the global response center is called, there is a 4.8 percent chance that the flight will be diverted for an immediate landing. Suppose the response center is called 8,465 times in a given year.

a) What is the expected number of diversions

b) What is the probability of at least 400 diversions

c) What is the probability of fewer than 450 diversions?

a) expected number of diversions μ is 406.32

b) the probability of at least 400 diversions is 0.6368

c) the probability of fewer than 450 diversions is 0.9861

Step-by-step explanation:

Given the data in the question;

n = 8465

π = 4.8% = 0.048

so expected number of diversions μ = nπ = 8465 × 0.048 = 406.32

and

σ = √(π(1 - π ) = √(8465 × 0.048(1 - 0.048 ) = √( 406.32 × 0.952 )

σ = √386.81664

σ = 19.6677

b) the probability of at least 400 diversions

P(at least 400 diversion ) = P( X ≥ 400 )

= P( X ≥ 399.5 )

so

z = (X - μ) / σ

we substitute

z = (399.5 - 406.32 ) / 19.6677

z = -6.82 / 19.6677

z = -0.35

so

P(Z > -0.35 ) = 0.500 + p( -0.35 ≤ z ≤ 0 )

= 0.5000 + p( 0 ≤ z ≤ 0.35 )

= 0.5000 + 0.1368

= 0.6368

Therefore, the probability of at least 400 diversions is 0.6368

c)  the probability of fewer than 450 diversions

P(fewer than 450 diversion ) = P( X ≤ 450 )

= P( X ≤ 449.5 )

so

z = (X - μ) / σ

we substitute

z = (449.5 - 406.32 ) / 19.6677

z = 43.18 / 19.6677

z = 2.20

so

P(Z ≤ 2.20 ) = 0.500 + p( 0 ≤ z ≤ 2.20 )

= 0.5000 + 0.4861

= 0.9861

Therefore, the probability of fewer than 450 diversions is 0.9861

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step-by-step explanation:

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.