The slope of the line passing through the points with coordinates (2,6) and (3,11) is ?
A.5
B.-5
C.-1/5
1/5

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

⊂⊃⊂⊃ω

step-by-step explanation:

i hope this : )

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