The polynomial - 16 + v. t+s, represents the height (in feet) of an object, where v, is the initial vertical velocity (in feet per second), s, is the initial height of the object (in feet), and is the time in seconds). Write a polynomial that represents the

height of the object. Then find the height of the object after 1 second.

Complete question is;

The polynomial -16t² + v_o(t) + s_o represents the height (in feet) of an object, where v_o is the initial vertical

velocity (in feet per second), s_o is the initial height of the object (in feet), and t is the time in seconds. Write a polynomial that represents the height of the object that has an initial velocity of 25 ft/s and initial height of 4ft. Then find the height of the object after 1 second.

A) Polynomial is h(t) = -16t² + 25t+ 4

B) h(1) = 13 ft

Step-by-step explanation:

A) We are given;

h = -16t² + v_o(t) + s_o

Where;

v_o = the initial vertical velocity

s_o = the initial height of the object

t = the time

We are given;

v_o = 25 ft/s

s_o = 4 ft

Thus, polynomial that represents the height is;

h(t) = -16t² + 25t+ 4

B) after a time of 1 second, height is;

h(1) = -16(1²) + 25(1) + 4

h(1) = -16 + 25 + 4

h(1) = 13 ft

its totaly b

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