Look at the graph shown below the blue line represents an _ of the graph

Given:

The graph of a function and a blue line.

To find:

The correct name for the blue line.

Solution:

Domain: It is the set of inputs. These are the x-values for which the function is defined.

Range: It is the set of outputs. These are the y-values for the function.

Asymptote: The function approaches to a line as x approaches to -∞ or ∞ but not intersect the line, then the line is known as asymptote.

y-intercept: It is the intersection point of the function and the y-axis.

From the given graph it is clear that the function approaches to the blue line as x approaches to -∞ but not intersect the blue line.

So, the blue line is an asymptote of the function.

Look at the graph shown below the blue line represents an asymptote of the graph.

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752