Sketch a graph of the function y=cos^1x , Part I: First, sketch at least two periods of the function y = cosx
: What are the domain and range of the function y=cosx

Part III: Restrict the domain of the function

so that it may be inverted. That is, select the portion of the graph of y=cosx

that is suitable for inverting. Mark that portion on your graph from Part I.
Part IV: Now draw the reflection of this new graph of y=cosx

across the line y = x. This is a graph of the function y = cos^1x

b. t=-25h+3

step-by-step explanation:

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.