So confused

which situations can be represented by an exponential function? select each correct answer.

on the highway, kareem's car gets 38 mpg.

shu fang has $25.75 deducted from her checking account every month.

a toad population is increasing by about 7.5% each year.

an event organizer finds each year's attendance for the past five years is about 4/5 of the previous year's attendance.

A toad population is increasing by about 7.5% each year.

An event organizer finds each year's attendance for the past five years is about 4/5 of the previous year's attendance.

Step-by-step explanation:

On the highway, Kareem's car gets 38 mpg.

This can be modeled with a linear relationship between the miles and the gallons of fuel needed.

Shu Fang has $25.75 deducted from her checking account every month.

Here we know that each month a constant amount is deducted from her, this is not an exponential relation.

A toad population is increasing by about 7.5% each year.

If the population initially was an amount P, after one year the population is P*1.075, after two years the population is P*(1.075)^2 and so on, this can be modeled with an exponential function where the years variable, the function will have the general form:

Population(y) = P*(1.075)^y

An event organizer finds each year's attendance for the past five years is about 4/5 of the previous year's attendance.

If the first year the population is X, the year after the attendance will be (4/5)X, and the year after this process applies again, so you have a 4/5 of the previous attendance, the attendance now is (4/5)^2*X

This also can be modeled with an exponential function, of the shape:

Attendance (y) = X*(4/5)^y, where again, y means years.

The thing you may notice is that in this case the model only works for the lapse of 5 years that the event organizer said.

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13

the first domain and range set to the left is matched with the top relation, and the second set the set in the middle goes with the bottom relation.