Acode is formed using four of these letters: a, b, i, k, n, o, and t. (note that the order of the letters in the code matters; for example, abik is a different code from baik.) the size of the sample space . the probability that the first three letters of the four-letter code are vowels .

Step-by-step explanation:

    Hence the size of the sample space is:

     since we have to fill in 4 places with the help of these 7 letters.

  so in first place we can select one out of any 7 letters, similarly for the second place as it is not mentioned that repetition is not allowed and the same can be done for third and fourth place.

Hence size of sample space is:

 Probability=(Number of favourable outcomes)/(Total number of outcomes)

Hence here the total number of outcomes=

Total number of favourable outcomes=outcomes that the first three letters are vowels= (since in the first place we have three choices for a vowel{A,I,0} similarly for second and third place and in the fourth place any one of the 7 letters could come)

Hence the probability(P) that the first three letters of the four-letter code are vowels is given by:

Hence, the Probability is:

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4