Using the ac method ax^2 +bx+c
how do i solve this problem? and check the answer back into equation? mark as brainlest on my list !

25x^2 -20x +4

25=5*5=1*25
4=2*2=1*4
Factor to get sum of-20
(5x-2)(5x-2)
solve 5x-2=0=>x=2/5 is root of multiplicity 2 for both functions.

So
find ac
list all products that equal ac
find the ones that add to b
rewrite
factor
undistribute
so

25x^2-20x+4
ac=4*25=100
what 2 numbers, when multipied together, results in 100 but adds to -20?, I did this in previous quesiton, the answer is -10 and -10

25x^2-10x-10x+4
(25x^2-10x)+(-10x+4)
(5x)(5x-2)+(-2)(5x-2)
factor out (5x-2)
(5x-2)(5x-2)
well, there is no equal sign, but we will assume it equals 0
(5x-2)^2=0
5x-2=0
5x=2
x=2/5