At how many points does the graph of the function y=16x^2-8x+1 intersect the x axis

Let's compute the discriminant using this formula

D = b^2 - 4ac

in this case, a = 16, b = -8 and c = 1

Plug these values into the formula to get

D = b^2 - 4ac
D = (-8)^2 - 4(16)(1)
D = 64 - 64
D = 0

Since the discriminant is 0, this means that there is exactly 1 solution. This 1 solution corresponds to exactly 1 root or x intercept

So this parabola touches the x axis at exactly one point 

The answer would be 24mm