Arectangle has a length of x inches and a width 2 inches less than the length. if the dimensions were tripled what would be the area of the new rectangle in terms o x

Originally we have
length = x
width = x-2
since the width is 2 inches smaller than the length

now let's triple each dimension. Multiply the expressions by 3 to get
new length = 3*x
new width = 3*(x-2) = 3x-6

Now onto the area
area = (length)*(width)
area = (3x)*(3x-6)
area = 3x*3x-3x*6
area = 9x^2 - 18x

So the new larger rectangle has area of 9x^2-18x

Ibelieve that c. recording would work best.