Mathematics, 06.10.2019 17:00 alicia186
Evaluate the indefinite integral as an infinite series ∫sinx /2x dx
Answers: 1
, divide the power series by 2x:![\displaystyle \frac{sin(x)}{2x} = \sum^{\infty}_{n = 0} \bigg[ \frac{(-1)^nx^{2n + 1}}{(2n + 1)!} \cdot \frac{1}{2x} \bigg]](/tpl/images/0294/3596/bc2f3.png)
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