Mathematics, 06.10.2019 08:40 velazquezemmy45

Jeanette wants to tile the floor of a room in her house. the square tiles measure 3/4 ft on each side. the room is 10 ft wide.
a. write an inequality to describe how many tiles are needed to make one row of tiles across the width of the room.
b. solve the inequality.
c. how many tiles should jeanette buy to form one row?

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Jeanette wants to tile the floor of a room in her house. The square tiles measure 3/4 ft on each side. The room is 10 ft wide.

10 divided by 3/4 is equal to 13.33 or 13 and 3/10 tiles

She needs 13 and 3/10 tiles across the room

Answer from: makayladurham19

a. The inequality will be: $\frac{3}{4}x\geq 10$

b. Solving the inequality: $x\geq 13.333...$

c. Jeanette should buy 14 tiles to form one row.

Step-by-step explanation:

Suppose, the number of tiles needed to make one row

Each square tiles measure $\frac{3}{4}$ ft on each side.

So, the total length of number of tiles $=\frac{3}{4}x\ ft$

Given that, the room is 10 ft wide.

So, the inequality will be: $\frac{3}{4}x\geq 10$

Solving the above inequality.....

$\frac{3}{4}x\geq 10\\ \\ 3x\geq 4(10)\\ \\ 3x\geq 40\\ \\ x\geq \frac{40}{3}\\ \\ x\geq 13.333...\\ \\ x\approx 14$

So, Jeanette should buy 14 tiles to form one row.

Answer from: Quest

answer: if you weigh 60 pounds on earth, on the moon you will weigh about 10 pounds. if you weigh 120 pounds on earth, you will weigh about 20 pounds on the moon. since weight is caused by the mass of two objects that are near each other, the bigger the objects, the more the force of gravity.

step-by-step explanation: if you weigh 60 pounds on earth, on the moon you will weigh about 10 pounds. if you weigh 120 pounds on earth, you will weigh about 20 pounds on the moon. since weight is caused by the mass of two objects that are near each other, the bigger the objects, the more the force of gravity.

Answer from: Quest

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

= $\sqrt{(9-6)^{2} +(12-6)^{2} } \\=\sqrt(45)=3\sqrt(5)$

side j'k'=distance between j' and k'

= $\sqrt{(3-2)^{2} +(2-4)^{2} } \\=sqrt(5)$

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

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