If parallelogram abcd was reflected over the y-axis, reflected over the x-axis, and rotated 180°, where would point a' lie?

[hint: place your coordinates in the blank with no parantheses and a space after the comma in the form: x, y.] (5 points)

The answer to the problem is as follows:

(x,y)−−−>(−x,y)
>it is reflect across y axis
(x,y)−−−−>(x,−y)
--->across x axis
 
rotate 180 (x,y) ---> (-x,-y)
 
so it's (-4,1) i am right

I hope my answer has come to your help. God bless and have a nice day ahead!

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12