Let p be a point between points s and t on 2004-01-01-02-00_files/i012.jpg. if st = 21, sp = 3b – 11, and pt = b + 4, solve for b.
a. –7
b. 7
c. 14
d. 32

If ST = 21, SP = 3b – 11, and PT = b + 4, the value of b would be 14.

Step-by-step explanation:

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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step-by-step explanation: