Aball is kicked upward with an initial velocity of 56 feet per second. the ball's height h (in feet) can be expressed as a function of time t (in seconds) by the equation h = -16t2 + 56t. how much time does the ball take to return to the ground?
a) 1.75 seconds
b) 2.50 seconds
c) 2.75 seconds
d) 3.50 seconds

  D)  3.50 seconds

Step-by-step explanation:

You are interested in the positive value of t such that h=0. Substituting 0 for h, we get ...

  0 = -16t^2 +56t

  0 = -16t(t -3.5) . . . . . factored form

The product is zero when the factors are zero. Here, the factor of interest is ...

  0 = t-3.5

  3.5 = t . . . . . add 3.5 to both sides

The ball takes 3.5 seconds to return to the ground.

the graph in the attached figure

step-by-step explanation:

we have

using a graphing tool

the graph in the attached figure

the roots are ( x-intercepts) x=-0.5,x=1,x=3

the y-intercept is the point (0,3)