If p(x) = x2 – 1 and q(x)=5(x-1), which expression is equivalent to (p – q)(x)?

5(x – 1) – x2 – 1
(5x – 1) – (x2 – 1)
(x2 – 1) – 5(x – 1)
(x2 – 1) – 5x – 1

Here is their argument. given the obtuse angle x, we make a quadrilateral abcd with ∠dab = x, and ∠abc = 90◦, and ad = bc. say the perpendicular bisector to dc meets the perpendicular bisector to ab at p. then pa = pb and pc = pd. so the triangles pad and pbc have equal sides and are congruent. thus ∠pad = ∠pbc. but pab is isosceles, hence ∠pab = ∠pba. subtracting, gives x = ∠pad−∠pab = ∠pbc −∠pba = 90◦. this is a preposterous conclusion – just where is the mistake in the "proof" and why does the argument break down there?

You decide instead to take the train there. the train will take 135 minutes. convert this into hours and minutes.

What is the solution to the equation? k/6.4=8.7 2.3 5.568 15.1 55.68