If f(x) = –x3, g(x) = 3x2 – 1, and h(x) = 2x + 5, what is the degree of [f o g o h](x)?

degree would be 6.

Step-by-step explanation:

Given : f(x) = –x³, g(x) = 3x² – 1, and h(x) = 2x + 5,

To find : what is the degree of [f o g o h](x)

Solution : We have given f(x) = –x³, g(x) = 3x² – 1, and h(x) = 2x + 5,

g o h(x) =  3(2x+5)² – 1

g o h(x)  = 3 ( 4x² + 25 + 20x) - 1.

g o h(x)  = 12x² + 75 + 60x -1.

g o h(x)  =  12x² + 60x - 74.

f o g o h(x) = –(12x² + 60x - 74)³.

If we open the cube then it would become in order of

Therefore, degree would be 6.

i will pick c put check it over to be sure

step-by-step explanation:

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