Arectangle has length 3 feet and width 1/4 foot. what is the area of the rectangle?

Find the vertex of the function given below y=x^2-6x+1

Which is a true statement comparing the graphs of x^2/6^2-y^2/8^2 = 1 and x^2/8^2-y^2/6^2 the foci of both graphs are the same points. the lengths of both transverse axes are the same. the directrices of = 1 are horizontal while the directrices of = 1 are vertical. the vertices of = 1 are on the y-axis while the vertices of = 1 are on the x-axis.

How do you solve a question like this?