Math plz

2. write an equation in slope intercept form of the line that passes through the given point and is parallel to the graph of the given equation.
(2,-1) ; y = 3/2x + 6
a. y = -3/2x + 1
b. y = -3/2x - 1
c. y = -3/2x + 2
d. y = -3/2x + 4

Y = 3/2x + 6slope here is 3/2.A parallel line will have the same slope.

y = mx + b
slope(m) = 3/2
(2,-1)...x = 2 and y = -1
now we sub and find b, the y int
-1 = 3/2(2) + b
-1 = 3 + b
-1 - 3 = b
-4 = b
so ur parallel line is : y = 3/2x - 4

u sure u wrote this question correctly ??