Hi i was having some problem with this question, its been a while since i had been in geometry. i think you foil, but im not sure.
solve for x. 2(x+4)(x+3)= 3(x+2)(x-1)

First, I would distribute the 2 out to the (x+4). 

2x+8. 

Next, use the foil method to multiply together 2x+8 and (x+3). 

2x^2 +14x+24. 

Do the same process for the other side. 

3(x+2)= 3x+6 

(3x+6)(x-1)= 3x^2+3x-6

Set the remaining products of each side of the equation equal to each other. 

2x^2 +14x+24=3x^2+3x-6. 

Now you must cancel out one side to make the equation equal to zero. Do this by doing the inverse operation on one side of the equation (each value with their like term). I am going to subtract the left side values from the right: 

This means: 
3x^2 minus 2x^2 equals 1x^2 (or just x^2).    

3x minus 14x equals -11x 

-6 minus 24 equals -30 

The equation should now look like this: 

0=x^2-11x-30

Reverse the order to get zero on the right side: 

x^2-11x-30=0

Hope this helps! Sorry if I made any careless mistakes (^^;)