Which of the x values are solutions to the inequality 4(2 – x) > –2x – 3(4x + 1)? check all that apply.
x = –1.1
x = –2.2
x = 0
x = –10
x = 10

We are to solve the inequality for the value of x

The options x = 0 and x = 10 represent the value of x

Given:

4(2 – x) > –2x – 3(4x + 1)

open parenthesis

8 - 4x > - 2x - 12x - 3

8 - 4x > - 14x - 3

collect like terms

- 4x + 14x > - 3 - 8

10x > -11

divide both sides by 10

x > -11/10

x > -1.1

All values greater than -1.1 represent x

Therefore, from the options, x = 0 or x = 10

Read more:

link

 and  

Step-by-step explanation:

The inequality is given as:  

Using distributive property [ ] and a little algebra, we have:

Taking all the x's to one side and number to another:

Now, of the 5 numbers shown, which of them are GREATER THAN ?

They are 0 and 10.

go hook jvc hgv cj xk jvc 6756

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3