![y=2x+3](/tpl/images/0442/9991/292a9.png)
Step-by-step explanation:
the general form of a line is:
![y=mx+b](/tpl/images/0442/9991/904ac.png)
where m is the slope, and b is the point where the line crosses the y-axis.
From the graph we can see that said line crosses the y-axis at
+3
the the b in our solution must be+3 , we willl have a result of the form:
![y=mx+3](/tpl/images/0442/9991/4a749.png)
That rules out options A and C
Now to calculate the slope we take two points where the graph passes, I will take the points:
![(-2,-1)and (0,3)](/tpl/images/0442/9991/4ed02.png)
tag the coordinates
![x_{1}=-2\\y_{1}=-1\\x_{2}=0\\y_{2}=3](/tpl/images/0442/9991/52eae.png)
and use the slope equation
![m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}](/tpl/images/0442/9991/6fb82.png)
substituting the values:
![m=\frac{3-(-1)}{0-(-2)} \\m=\frac{3+1}{2}\\ m=\frac{4}{2} \\m=2](/tpl/images/0442/9991/27815.png)
the slope of the line is 2, so the equation of the line is:
![y=2x+3](/tpl/images/0442/9991/292a9.png)
which is option B