What is the ratio of the area of the inner square to the area of the outer square?

a: (a-b)2=b2/a2

b: a2-b2/a2

c: (a-b)2/(a+b)2

d: (ab)2/(a+b)2

Step-by-step explanation:

Since, By the given diagram,

The side of the inner square = Distance between the points (0,b) and (a-b,0)

Thus the area of the inner square = (side)²

Now, the side of the outer square = Distance between the points (0,0) and (a,0),

Thus, the area of the outer square = (side)²

Hence, the ratio of the area of the inner square to the area of the outer square

I got this fraction:

frac{(a-b)^2+b^2}{a^2}

(I got the answer correct)

Hope this is helpful :)

Step-by-step explanation:

yes

yes yes yes

i got 10.28 but that rounds up to 10.3