Given: abcd is a rhombus ac = 3x + 1, and bd = 4x + 2 the area of a rhombus can be represented by the formula a= 1 2 d1d2 where d1 and d2 are diagonals of the polygon. which expression represents the area of the rhombus? \

A = 6x² + 5x + 1

Step-by-step explanation:

The area of a rhombus is where d₁ is one diagonal and d₂ is the other diagonal.

If we have the rhombus ABCD, the diagonals are AC and BD.

The problem tells us that AC = 3x + 1 and BD = 4x + 2

Substituting this in our formula for the area and simplifying as much as we can (by factorizing) we get:

Therefore the area is A = (3x + 1) (2x + 1). If you want to solve the parenthesis you'd get A = 6x² + 5x + 1

third option: 6x+8

step-by-step explanation:

we can see that the given question is a sum of series and the values of n vary from 0 to 3

the first term will be:

when n=0, [(0)*x+2] => (0+2) => 2

when n=1, [(1)*x+2] => (x+2) => x+2

when n=2, [(2)*x+2] => 2x+2

when n=4, [(3)*x+2] => 3x+2

so adding up all the terms will give us:

=2+x+2+2x+2+3x+2

=x+2x+3x+2+2+2+2

=6x+8

so,

third option is the correct answer ..

where is the image?

step-by-step explanation: