Arock climber descends from a peak at a rate of 1/20 vertical km each minute.
what is the climber's total change in elevation in 10/11 minutes?
answer is a simplified fraction
i (sometimes) mark brainliest!

This can be solved by using the speed formula:

S = d/t

Where s is the speed in km/ min

D is the distance in km

And t is the time in min

So the unknown is distance

D = St

D = (1/20 km/min) ( 11/10 min)

D = 11/200 km

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).