Triangle rst has vertices r(2, 0), s(4, 0), and t(–3, –1). the image of triangle rst after a rotation has vertices
r'(0, –2), s'(0, –4), and t'(–3, –1). which rule describes the transformation?
r0, 90°
r0, 180°
r0, 270°
r0, 360°

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

the answer for your question is

step-by-step explanation:

its line 2 i just added the rest or else it wouldn't let me answer

slope =   (y2 -y1) ÷ (x2 -x1)

slope = (0 -0) / (-5, -7)

slope = 0 / -12 = 0

the slope of the line is zero.   it is perfectly horizontal.

step-by-step explanation: