Probability theory predicts that there is 77.6% chance of a particular soccer player making 2 penalty shots in a row. if the soccer player taking 2 penalty shots is simulated 2500 times, in about how many simulations would you expect at least 1 missed shot?

In about 560 simulations we would expect at least 1 missed shot.

Step-by-step explanation:

Probability theory predicts that there is 77.6% chance of a particular soccer player making 2 penalty shots in a row.

⇒ Probability of not missing a shot = 0.776

So, Probability of missing at least one shot = 1 - 0.776

                                                                      = 0.224

So, Chance of missing at least one shot = 22.4%

A shot is simulated 2500 times ⇒ n = 2500

Required simulations in which we would expect one shot missed = Probability of missing at least one shot × Number of simulations

⇒ Required simulations = 0.224 × 2500

                                          = 560

Hence, in about 560 simulations we would expect at least 1 missed shot.

walter needs to make at least 5 more cookies but no more than 40. 5 ≥ x ≥ 40;

step-by-step explanation:

walter has to make a minimum of 20 cookies. he already has 15 cookies made, so he must make 5 more to meet the minimum.

the maximum amount of cookies he can make is 55. he already has 15, so he has to make no more than 40 more cookies to meet the maximum.