Aline contains the points (8, 9) and (–12, –7). using point-slope form, write the equation of the line that is parallel to the given line and that passes through (–5, –15).

For the answer to the question above,
The slope of the line of the line is calculated through the equation,
m = (y2 - y1) / (x2 - x1) 

Using the first two points in the given,
 m = (-7 - 9) / (-12 - 8) = 4/5

The line parallel to this has also a slope of 4/5. Through the point-slope form, the equation of the second line is,
 y - -15 = (4/5)(x - -5)

Simplifying gives the answer of,
y = (4/5)x -11

Eliminating the fraction, 
5y = 4x - 55

I hope my answer helped you.

Hello there.
A line contains the points (8, 9) and (–12, –7). Using point-slope form, write the equation of the line that is parallel to the given line and that passes through (–5, –15).m = (y2 - y1) / (x2 - x1)