Find the x-intercepts of the parabola with vertex (2,13) and y-intercept (0,5). write your answer in this form: (x1,,y2). if necessary, round to the nearest hundredth.

The answer to the question is as follows:

 I would start by setting up an equation in vertex form. 
y=a(x-2)^2 +13 

To find a, sub in (0,5) 
5=a(0-2)^2 +13 
-8=4a 
a=-2 

y=-2(x-2)^2 +13 

Set y equal to 0: 

0=-2(x-2)^2 +13 
-13=-2(x-2)^2 
6.5 = (x-2)^2 
+/- square root 6.5 = x-2 

x= 4.549, -0.549

I hope my answer has come to your help. God bless and have a nice day ahead!