Which inequality will have a solid boundary line and a shaded region above its graph?

x − y ≥ 3

2x − 3y ≤ 3

3y − x < 2

2x + y < 7

Step-by-step explanation:

The first inequality is the one that have a solid boundary line and a shaded region above its graph.

First of all, when the inequality signs are , the boundary line isn't solid. When the inequality signs are , the bounday line is solid. The reason of this is because the second pair of relations involve equivalen, which refer to all solution on the boundary line.

Having said that, the possible answers are the first and second one, because they have   .

Now, to know if the shaded are is above the line, we need to evaluate the expression at (0,0).

In the first inequality, we have

which is false.

The second inequality

which is true.

Therefore, the second inequality has a shaded region above its line. You can chek this out in the image attached.

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!