Aline segment has endpoints at (–4, –6) and (–6, 4). which reflection will produce an image with endpoints at (4, –6) and (6, 4)?

a. a reflection of the line segment across the x-axis
b. a reflection of the line segment across the y-axis
c. a reflection of the line segment across the line y = x
d. a reflection of the line segment across the line y = –x

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1

(x+3)(x+7)

step-by-step explanation: