![\dfrac{\mathrm d}{\mathrm dx}\left[3x^2\right]=\dfrac{\mathrm d}{\mathrm dx}\left[xy^2+1\right]](/tpl/images/0494/6117/f2e2b.png)
has slope 
. In point-slope form, the line's equation is
Suppose the curve defined by the equation 3x^2 = xy^2 + 1. answer the following.
a) calculate...
Mathematics, 03.02.2020 00:55 glowbaby123
Suppose the curve defined by the equation 3x^2 = xy^2 + 1. answer the following.
a) calculate dy/dx . explain its meaning.
b) find the tangent line to the curve at the point (1, 2)
me!
Answers: 2
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