What is the vertex and transformation of f(x)=-2(x+3)^2

I am not sure about the transformation but i think the vertex is (-3,2)

If the original function is f(x)=x^2
to movve a function to the right c units, subtract c from every x
to vertically shrink a function by a factor of p, multiply whole function by p
to flip it over the x axis, multiply whole funtion by -1

so
f(x)=x^2
added 3 to every x (moved -3 units to right)
f(x)=(x+3)^2
vertically shrunk by a factor of 2
f(x)=2(x+3)^2
flipped about the x axis (times -1 whole function)
f(x)=-2(x+3)^2

transformations is vertically compressed by a factor of 2 and moved to the left 3 units and reflected about the x axis

the vertex:
in form
f(x)=a(x-h)^2+k
the vertex is (h,k)
f(x)=-2(x-(-3))^2+0
vertex is (-3,0)

Gotta be d the music of previous eras