The vertices of a quadrilateral in the coordinate plane are known. how can the perimeter of the figure be found?

If the vertices of a quadrilateral in the coordinate plane are known, to solve the perimeter of the given quadrilateral, the distance formula to two points should be used. The distance of vertices 1 and 2 should be solved, then vertices 2 and 3, then 3 and 4, and then vertices 4 and 1. Then add all the distance to solve the perimeter.

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

2nd one in the first row is correct