Gary bought a car for $40,000. if v = 40,000(.85)t represents the value of the car after t years, how long will it take the car to be worth less than one-fourth of its purchase price? a) 4 years b) 6 years c) 8 years d) 9 years

D) 9 years.

Step-by-step explanation:

We have been given that Gary bought a car for $40,000 and equation represents the value of the car after t years.

First of all we will find the one-fourth of 40,000.

To find the time it will take the car to be worth less than one-fourth of its purchase price, we will substitute V=10,000 in our given equation.

Let us divide both sides of our equation by 40,000.

Let us take natural log of both sides of our equation.

Using natural log property we will get,

Upon rounding our answer to the nearest year we will get,

Therefore, it will take 9 years the car to be worth less than one-fourth of its purchase price and option D is the correct choice.

-1/2 +2

step-by-step explanation:

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