the data set represents the heights of players on a soccer team.

5.75, 5.16, 6, 5.25, 5.5, 6.25, 5.66, 5.33, 5.33, 6, 5.75. 5.66, 5.16

what is the interquartile range (iqr) of the data set?

a. 0.585
b. 1.09
c. 5.6
d. 5.875

Option: A(0.585)

Step-by-step explanation:

After arranging our data in ascending order we get that:

5.16   5.16   5.25   5.33   5.33   5.5   5.66   5.66   5.75   5.75   6   6   6.25

Quartiles divide a rank-ordered data set into four equal parts. The values that divide each part are called the first, second, and third quartiles; and they are denoted by Q1, Q2, and Q3, respectively.

The interquartile range is equal to Q3-Q1.

So, the Median()of data is given by: 5.66

also the lower half is:

5.16   5.16   5.25   5.33   5.33   5.5

Hence, the middle value or median of this lower half of this data lie between 5.25 and 5.33 which is 5.29.

Hence, =5.29

Similarly the upper half is:

5.66   5.75   5.75   6   6   6.25

Hence, the middle value or median of this upper half of this data lie between 5.75 and 6 which is 5.875

Hence, =5.875

Hence, the interquartile range=

Hence, option A is correct.

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

168

step-by-step explanation:

i am pretty sure that the answer is 168