The ideal width of a certain conveyor belt for a manufacturing plant is 50 in. conveyor belts can vary from the ideal width by at most 7/32 in.

Answer;

The acceptable width is 49 25/32 and 50 7/32

That is; 49 25/32 ≤ x ≥ 50 7/32

Explanation;

-If the ideal is 50 and the max variation is 7/32 inches, then that's 7/32 under 50 and 7/32 over 50.

Therefore; 50-7/32= 49 25/32, and 50+7/32 = 50 7/32.

x ≤ 50 7/32 and x ≥ 49 25/32

Thus; the acceptable width is 49 25/32 ≤ x ≥ 50 7/32.

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step-by-step explanation:

distance formula is d=√(x2-x1)^2   +   (y2-y1)^2

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step-by-step explanation: