Haji rows his canoe 10 mph in still water. he noticed one day that he could row 4 miles upstream in the same amount of time he could row 6 miles downstream. what was the approximate speed of the current that day?

Let speed of current be x mph 

upstream speed = ( 10-x) mph 

downstream speed = ( 10 + x) mph 

time = distance / speed 

4/ ( 10-x) = 6/ (10+x ) 

cross multiply 

60-6x = 40+4x 

10x = 20 

x = 2 mph answer 

check 

4/ (10-2) = 4/8 = 1/2 hour 

6/ (10+2) = 6/12 = 1/2 hour

answer:

the answer on the test is 2.0mph

step-by-step explanation:

thats all hope i