We learned that division expressions that have the same quotient and remainder are not necessarily equal to each other explain how this is possible

Division expressions that have the same quotient and remainder are not necessarily equal to each other. This is possible because each expressions have different numbers so the calculation can be different

Division is breaking the number up into the equal number of parts.

We learned that division expressions that have the same quotient and remainder are not necessarily equal to each other. For example when we get 20 divided by 4 then If we take 20 things and put them into four equal sized groups, there will be 5 things in each group. Therefore the answer is 5 and hence it will not be any remainder (remainder is 0).

Another example is when we get 21 divided by 4 then If we take 21 things and put them into four equal sized groups, there will be 5 things in each group and the remainder of 1.

Third example is when we get 26 divided by 5 then If we take 26 things and put them into four equal sized groups, there will be 5 things in each group and the remainder of 1.

Division expressions that have the same quotient and remainder are not necessarily equal to each other. This is possible because each expressions have different numbers so the calculation can be different. The difference is that the remainders are not the same in every expressions.  The first remainder is 1 part out of 4, when the third remainder is 1 part out of 5.

Grade:    5

Subject:  Math

Chapter:  expressions

Keywords:  division, quotient, remainder, expressions, equal

i cant see the graph

step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.