Solve the following equation: |7 – (24 ÷ | 3-6 |)|
(a)15(b)-12(c)1(d)-1

PEDMAS

The rule is Paranthesis First

|7-(24÷|3-6|)|

|7-(24÷|-3|)|

Now we have to get the -3 outside the 2 Lines but the lines are saying that if the number inside is negative when you get it outside it has to be positive.

|7-(24÷3)|-

|7-(8)|

|7-8|

|-1|

= 1