In the circle, ab= 34, bc = 12 and cd= 8

Option A. x = 61

Step-by-step explanation:

If two secants are intersecting each other on a point outside the circle then by theorem of intersecting secants

(x + CD)×CD = AC×BC

(x + CD)×CD = (AB + BC) × BC

Here AB = 34, BC = 12, and CD = 8

(x + 8) × 8 = (34 + 12) × 12

8x + 64 = 46×12 = 552

8x = 552 - 64 = 488

x = 488 ÷ 8

x = 61

Therefore option A. x = 61 will be the answer.

answer: a rhombus has two lines of symmetry that run through one vertex to the one directly across it. unlike a square, planes through the center of each edge of a rhombus do not yield mirrored sides.

step-by-step explanation:

135 is your answer

step-by-step explanation:

try 180 times three then divide that number by 4 (sides) to get your answer. im glad to : )