Jillian has three different bracelets (x, y, and z) to give to her friends as gifts in any order she prefers. if bracelet y is chosen first, in how many ways can jillian give out the bracelets?
a)1
b)2
c)3
d)4

Answer

b)2

Explanation

There are 3 bracelets to be chosen regrades of the order.

If this was the case, there would be 3! ways.

3! = 3 × 2 × 1

   = 6 ways.

But one of the bracelets is chosen first. So, there are only 2 bracelets left to be interchanged.

∴ 2! = 2 × 1

       = 2

Y X Z  and Y Z X

B

Step-by-step explanation:

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