Explain why the intercepts, on their own, cannot be used to graph the relation 5x+9y= 0.

5x + 9y = 0

to find the x int, sub in 0 for y and solve for x
5x + 9(0) = 0
5x = 0
x = 0

to find the y int, sub in 0 for x and solve for y
5(0) + 9y = 0
9y = 0
y = 0

the reason u cannot use just the intercepts is because the line goes through the origin (0,0)The intercepts coincide giving u only 1 point...and that is not enough to graph a line

The first one, i believe, would be correct. all the others have one thing in common, and that's that they have repeating numbers. in the second one, x and y have repeating 6's and 3's, and in the third, x and y have repeating 6's as well. in the last one, there are repeating 3's. the first one has no repeating numbers.