Ben is making math manipulatives to sell. he wants to ay least sell $450. each manipulative costs $18 to make. he is selling them for $30 each. what is the minimum number he can sell to reach his goal?

Ben can sell 38 pieces of math manipulatives to reach his goal

The division operation is one of the basic arithmetic operations

Common signs used are or

The division is written by placing the numerator above the denominator with a horizontal line between them or use a slash with the numerator's position and the denominator is parallel

The division is actually an iterative subtraction operation (as many as the number of divisors)

Division is the opposite of multiplying

The general form of division can be stated by:

example:

The form of division can also be expressed in terms of fractions

In the number above, the form of fraction obtained is the form of mixed fractions

Mixed fractions consist of integers and ordinary fractions

Division operation statement:

"7 divided by 3 equals 2 remainder 1

Ben wants to at least sell $450 math manipulatives

each manipulative costs $18 to make

selling price : $30 each

the minimum number of math manipulatives he can sell to reach his goal

the benefits of each math manipulative he sells:

benefit = selling price - making price

benefit = $30 - $18

benefit =$12

Because what Ben wants is to make a profit at least $450, the amount that must be sold:

=

we round up :

Divide 80 in a ratio of 3: 2

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percent of 19.5 is 70.59

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The average weight of the top 5 fish

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Keywords: division, math manipulatives, sell

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}