Iam in desperate need of !

ben uses a compass and a straightedge to bisect angle pqr, as shown below:

the figure shows two rays qp and qr having a common end point q. an arc drawn from q cuts the ray qp at a and the ray qr at b. two small arcs intersect between the lines qp and qr. the point of intersection of the arcs is labeled s. the points q, s, and t are joined with a line.

which statement best explains why ben uses the same width to draw arcs from a and b which intersect at s?

bq = bs when ∠aqs ≅ bqs.
aq = as when ∠aqs ≅ bqs.
∠aqs ≅ bqs when as = bs and aq = bq.
∠aqs ≅ bqs when as = bq and bs = aq.

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.

y-3=-3/2(x+4)

ur very much welcome