Mathematics, 29.01.2020 11:45 yugbug44owwc7w
the difference between the roots of the equation 3x^2+bx+10=0 is equal to 4 1/3 . find b.
Answers: 1
![\textit{and their root difference is }4\frac{1}{3}\implies \cfrac{13}{3}\qquad so \\ \quad \\ \left[ \cfrac{-b+\sqrt{b^2-4(3)(10)}}{2(3)} \right]-\left[ \cfrac{-b-\sqrt{b^2-4(3)(10)}}{2(3)} \right]=\cfrac{13}{3} \\ \quad \\ \left[ \cfrac{-b+\sqrt{b^2-4(3)(10)}}{6} \right]+\left[ \cfrac{+b+\sqrt{b^2-4(3)(10)}}{6} \right]=\cfrac{13}{3} \\ \quad \\ \cfrac{-b+\sqrt{b^2-4(3)(10)}+b+\sqrt{b^2-4(3)(10)}}{6}=\cfrac{13}{3} \\ \quad \\ \cfrac{2\sqrt{b^2-4(3)(10)}}{6}=\cfrac{13}{3}](/tpl/images/0481/7046/fc7f0.png)
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the difference between the roots of the equation 3x^2+bx+10=0 is equal to 4 1/3 . find b....
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