Triangle mno is congruent to right triangle rst with a right angle at vertex r. if the slope of rs is -1/5, what must be true?

the slope of tr is 5
the slope of om is 5
the slope of mn is -1/5
the slope of no is 1/5

Option 1 must be true .i.e., Slope of TR is 5

Step-by-step explanation:

Given: Δ MNO ≅ Δ RST

          ∠R = 90°

          Slope of RS =  

We are given ΔMNO is congruent to ΔRST but we are not told which side is equal to which side.

Means in ΔRST we know ∠R is right angle but in ΔMNO we dont know which angle is right angle.

⇒ We can't say anything about slopes of sides of ΔMNO.

Therefore, Option 2 , 3 , 4 can be true but not sure.

But, in ΔRST

∠R is right angle means RS ⊥ RT

Slope of RS,

Let Slope of RT be

We know that product of slopes of perpendicular lines are equal to -1.

Therefore, Option 1 must be true .i.e., Slope of TR is 5

is it 35

step-by-step explanation:

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)