On a scale drawing of a museum, two water fountains are 10 inches apart. the actual distance between them is 400 feet. on the same drawing, the distance between two exhibits is 3.125 inches. what is the actual distance between these two exhibits? 13 feet 125 feet 313 feet 425 feet

The actual distance between these two exhibits = 125 feet.

Step-by-step explanation: Two water fountains are 10 inches apart on a scale of drawing museum

The actual distance between them is 400 feet.

On the same drawing, the distance between two exhibits is 3.125 inches.

To Find : What is the actual distance between these two exhibits?

Since Two water fountains are 10 inches apart on a scale of drawing museum and The actual distance between them is 400 feet.

⇒ 10 inches = 400 feet

So, 1 inch = 400/10

⇒1 inch = 40 feet

Since we are given that  the distance between two exhibits is 3.125 inches.

So , the actual distance between two exhibits (i.e.in feet ) (Using 1 inch = 40 feet)

= 3.215*40

= 125 feet

Thus , The actual distance between these two exhibits = 125 feet.

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,