Mike has a stack of 10 cards numbered 1 to 10 if he randomly chooses two cards without replacing the first one drawn what is the probability that mick would pick two cards that are prime numbers?

He could pick 1, 2, 3, 5, 7, 9. So you could pick two of any of these numbers. They are all prime numbers.

Magic man is here, but unfortunately he is broke won’t you him out

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)