In the below system, solve for y in the first equation.
x − 3y = −6
2x − 7y = 10
a. 1/3x+2
b. -1/3x+6
c. -x+2
d. -1/3x+2

The answer is the option A

Step-by-step explanation:

we have

-----> first equation

-----> second equation

Solve for y in the first equation

That means------> isolate the variable y in the first equation

Divide by both sides

you should at least use a calculater

step-by-step explanation:

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."